3x^2+80x-11500=0

Solution for 3x^2+80x-11500=0 equation:

3x^2+80x-11500=0

a = 3; b = 80; c = -11500;
Δ = b2-4ac
Δ = 802-4·3·(-11500)
Δ = 144400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144400}=380$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-380}{2*3}=\frac{-460}{6}
=-76+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+380}{2*3}=\frac{300}{6}
=50
$